Question

Q 16)if the momentum is increased 13% then Kinetic energy will increase A) 27% B) 33% C) 43% D) 57% ​

Answer 1

Given:

Momentum is increased by 13%.

To find:

Increase in Kinetic Energy?

Calculation:

• Let initial momentum and kinetic energy be P and KE respectively.

$KE = \dfrac{ {P}^{2} }{2m}$

Now, new momentum = P × 113/100.

$KE_{f} = \dfrac{ {(P \times \frac{113}{100} )}^{2} }{2m}$

$\implies KE_{f} = \dfrac{ {P}^{2} }{2m} \times 1.2769$

$\implies KE_{f} = KE \times 1.2769$

So, increase in Kinetic Energy is :

$= \dfrac{KE(1.2769 - 1)}{KE} \times 100\%$

$= 0.2769 \times 100\%$

$= 27.69 \%$

So, KE increases by approx 27%.