Q.16 of 17
Drive the following equations of
motion using graphical method
(1+1+1)
a. Draw graph and write
considerations
b. Derive y= u + at
c. Derive s = ut + 12 at2
(3 marks)
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Answer:
Explanation:
Let us Consider the linear motion of a body with an initial velocity u. Let the body accelerate uniformly and acquire a final velocity v after time t.
Here, The velocity-time graph is a straight line AB
So, According to the velocity-time graph is
At t=0, initial velocity =u=OA
At t=t, final velocity =v=OC
The distance S traveled in time t = area of the trapezium OABD
s=(
2
1
)×(OA+DB)×OD
s=(
2
1
)×(u+v)×t
Since v=u+at
s=(
2
1
)×(u+u+at)×t
s=ut+(
2
1
)at
2
This is the required expression.
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