q-16ka solution plzzzz
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2
Hope this helps u mate
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sifat74:
thanks
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0
Answer:3
Step-by-step explanation:
a^2/bc + b^2/ca + c^2/ab
(a^4.bc+ b^4.ca + c^4.ab) / a^2.b^2.c^2 (lcm)
abc(a^3 + b^3 + c^3) /a^2.b^2.c^2 (factorise)
a^3+b^3+c^3/abc (cancel abc and a^2.b^2.c^2 to abc)
(if a+b+c=0, then a^3+b^3+c^3=3abc identity)
3abc/abc = 3
therefore, solved
answer=3
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