Question

Q. 17 A cable carries a current of 1 A vertically upward. The magnetic field produced by
it at a point 10 cm north will be:
A)2x10-6 Tesla west
C)2x10-8 Tesla west
B) 2x10-6 Tesla
D) 2x10-8 Tesla vertically upward

Answer 1

Given:

A cable carries a current of 1 A vertically upward.

To find:

The magnetic field produced by

it at a point 10 cm north.

Calculation:

The general expression for Magnetic Field Intensity due to an infinite wire is:

$\therefore \: B = \dfrac{\mu_{0}}{4\pi} \bigg \{ \dfrac{2i}{r} \bigg \}$

Putting the values in SI unit:

$= > \: B = \dfrac{\mu_{0}}{4\pi} \bigg \{ \dfrac{2 \times 1}{ (\frac{10}{100}) } \bigg \}$

$= > \: B = \dfrac{\mu_{0}}{4\pi} \bigg \{ \dfrac{2 \times 1}{0.1 } \bigg \}$

$= > \: B = \dfrac{\mu_{0}}{4\pi} \bigg \{2 \times 10 \bigg \}$

$= > \: B = \dfrac{\mu_{0}}{4\pi} \bigg \{20 \bigg \}$

$= > \: B = {10}^{ - 7} \times 20$

$= > \: B = 2 \times {10}^{ - 6} \: tesla$

• Now , if we apply RIGHT HAND THUMB RULE, we will get the direction as west.

So, final answer is:

$\boxed{ \bf{ \: B = 2 \times {10}^{ - 6} \: tesla \: (west)}}$

Answer 2

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