Question

Q.17 A car of mass 800kg is travelling around a circular path of radius 200m with a speed of 10ms⁻¹. Its angular momentum is *

(a) 1.6 x 104 kgm²s⁻¹

(b) 1.6 x 106 kgm²s⁻¹

(c) 1.6 x 108 kgm²s⁻¹

(d) 1.6 x 1010 kgm²s⁻¹

​

Answer 1

Explanation:

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Answer 2

Answer:

The angular momentum is (b)  1.6 × $10^{6}$ $kgm^{2} s^{-1}$

Explanation:

Any rotating object's characteristic is determined by the moment of inertia times angular velocity.

The sum of a rotating body's moment of inertia and angular velocity determines this property.

The formula for angular momentum (L) is L = r×p or L = mvr,

where L is the object's distance from the axis of rotation multiplied by the linear momentum.

It is given that

The mass of the car (m) = 800 kg

The radius of the circular path (r) = 200 m

Vehicle speed (v) equals 10 m/s

Now, Putting the values in the formula for angular momentum, we have

L = mvr = 800×10×200 = 1.6 × $10^{6}$ $kgm^{2} s^{-1}$

Therefore, the angular momentum is (b)  1.6 × $10^{6}$ $kgm^{2} s^{-1}$

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