Q.17. ACD is an exterior angle of triangle ABC. If angle A = 50°, then find angle
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Step-by-step explanation:
Let ∠A = 2x∘.
Then ∠B = (4x)∘; ∠C = (5x)∘ and ∠D = (7x)∘
Since the sum of the angles of a quadrilateral is 360o, we have:
2x + 4x + 5x + 7x = 360∘
⇒ 18 x = 360∘
⇒ x = 20∘
∴ ∠A = 40∘; ∠B = 80∘; ∠C = 100∘; ∠D = 140∘
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