Q 17: an electric heater of resistance 8 ? Draws 15 a from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.
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Answer:
Given,
Resistance in electric heater , R = 8 ohm
Current , I = 15 A
Time taken , t = 2 hrs = 3600*2 sec = 7200 sec
The rate at which work is done by a source of emf in maintaining an electric current through a circuit is called the electric power of the circuit.
Power = current * voltage
Thus ,
The rate at which heat is developed in 2 hr is known as its power ,
P= I^{2} RP=I
2
R
on putting the values,
= 15*15 * 8
= 1800 Watt.
Thus the rate at which heat is developed in heater is 1800 Watt.
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