Math, asked by shilpyverma1212, 3 months ago

Q 17 Find two numbers such that when twice the first number is added to three times the second number, the result is 24 and when the first is added to twice the
second, the result is 23.
Ops: A.
0 -21, 22
B.
0 -22, 21
C. 34, 32
@-23, 21​

Answers

Answered by Anonymous
1

option "c" is the answer .

Thanks

Answered by swethassynergy
0

The first number is - 21 and second number is 22 and Option A is correct.

Step-by-step explanation:

Given:

When twice the 1st  number is added to three times the 2nd   number  , the result is 24.

And  the 1st  number is added to twice the 2nd   number , the result is 23.

Formula Used:

Finding the solution  of a pair of linear equations by Elimination method.

Solution:

Let the first no. is  x and second no. is y.

Given When twice the 1st  number is added to three times the 2nd number   , the result is 24.

2 x+ 3 y = 24               --------equation no.01

And  the 1st  number is added to twice the 2nd   number , the result is 23.

x+2 y=23                         -------- equation no.02

Multiplying equation 02  by 2.

Then  2 x+4 y=46       ------------  equation no.03

Subtracting equation 01 with  equation 03.

Then  y= 22

Puting the value of y=22  in  equation 02.

Then   x + 44=23

             x=  - 21

Thus, the first number is - 21 and second number is 22 and Option A is correct.

Question:

Q 17 Find two numbers such that when twice the first number is added to three times the second number, the result is 24 and when the first is added to twice the second, the result is 23.

Ops:

A. -21, 22

B.  -22, 21

C.  34, 32

D.  -23, 21

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