Q. 17. In the adjoining figure PQR is a triangle and PQ = PR and LQ = 90°. Find the values of other
two angles of the triangle ?
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Answer:
It is given that
PQ=8cm and QR=6cm
∠PQR=90
∘
Using Pythagoras Theorem
PR
2
=PQ
2
+QR
2
Substituting the values
PR
2
=8
2
+6
2
By further calculation
PR
2
=64+36=100
PR=√100
So we get
PR=10cm
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