Question

Q.17:#include int main() { int x; for(x=-1; x<=10; x++) { if(x < 5) continue; else break;
printf("IndiaBIX"); } return 0; }
a) O O times
b) O 11 times
c) O 10 times
d) Infinite times​

Answer 1

Answer:

a) 0 times

Explanation:

The condition x<5 is true until x=5, so the true block executed. The code after the continue statement(including printf("IndiaBIX");) will not executed and go to increment step(x++). Again the loop is continued.

When x=5, then else block executed, it has break statement, So loop is terminated.

Here the control never go to printf("IndiaBIX"); statement.

Answer 2

Answer:

Answer to this question will be a) O O times

Explanation:

Up to x=5, the condition x5 is true, hence the true block was performed. The code that follows the continue clause, including printf("IndiaBIX");, is not run and instead moves to the step(x++) increment. The loop is repeated once more. When x equals 5, the else block is executed. It contains a break statement, which ends the loop. The control in this case never makes the printf("IndiaBIX"); statement.

Hence , the answer will be a) O O times

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