Question

Q 17. Prove that:
(cosec A sin A) (sec A -
cos A) (tan A + cot A) = 1​

Answer 1

Answer:

your answer attached in the photo

Answer 2

Step-by-step explanation:

solving RHS

(cosecA sinA) (secA-cosA) (tanA+cotA)

hence we know

cosec=1/sin

sec=1/cos

cot=1/tan

now

=(1/sinA*sinA)(1/cosA-cosA) (tanA+1/tanA)

=(1)(1-cos^2A/cos)(tan^2A+1/tanA)

=(sin^2A/cosA)(sec^2A/tanA)

=on solving

=sinA/sinA

=1

hence LHS=RHS