Math, asked by kumaresh7, 9 months ago

Q.17 - The base of a parallelogram is (X + 2), altitude to the base is (X-
6) and the area is (X^2 - 4), find out its actual area.

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Answers

Answered by DHANUS2006
2

Answer:

hi

Step-by-step explanation:

Length of parallel sides of a parallelogram are equal.

So, the sum of length of parallel sides= 2(x+4)

Altitude to the base= (x-3)

Area of parallelogram= 1/2*(sum of parallel sides)*(altitude between parallel sides)

Area of parallelogram= 1/2*2(x+4)*(x-3)

x^2-4= x^2-3x+4x-12

x^2 cancel out each other

-4= x-12

x= 12-4

x=8

So, area of parallelogram= x^2-4= 8^2-4= 60

Answered by BrainlyRaaz
53

Answer:

  • Area of parallelogram = 96 cm^2

Given :

  • The base of a parallelogram is (x +2).

  • Altitude to the base is (x - 6).

  • The area is (X^2 - 4).

To find :

  • its actual area =?

Step-by-step explanation:

Length of parallel sides of a parallelogram are equal.

So, the sum of length of parallel sides= 2(x+2)

Altitude to the base= (x - 6)

Area of parallelogram= 1/2*(sum of parallel sides) × (altitude between parallel sides)

Area of parallelogram= 1/2 × 2(x+2)× (x-6)

x^2 - 2 = x^2 - 6x + 2x-12

x^2 cancel out each other

-2 = x-12

x= 12- 2

x = 10

Hence , area of parallelogram= x^2 - = 10^2 - 4 = 96 cm^2

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