Q.17 - The base of a parallelogram is (X + 2), altitude to the base is (X-
6) and the area is (X^2 - 4), find out its actual area.
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Answers
Answer:
hi
Step-by-step explanation:
Length of parallel sides of a parallelogram are equal.
So, the sum of length of parallel sides= 2(x+4)
Altitude to the base= (x-3)
Area of parallelogram= 1/2*(sum of parallel sides)*(altitude between parallel sides)
Area of parallelogram= 1/2*2(x+4)*(x-3)
x^2-4= x^2-3x+4x-12
x^2 cancel out each other
-4= x-12
x= 12-4
x=8
So, area of parallelogram= x^2-4= 8^2-4= 60
Answer:
- Area of parallelogram = 96 cm^2
Given :
- The base of a parallelogram is (x +2).
- Altitude to the base is (x - 6).
- The area is (X^2 - 4).
To find :
- its actual area =?
Step-by-step explanation:
Length of parallel sides of a parallelogram are equal.
So, the sum of length of parallel sides= 2(x+2)
Altitude to the base= (x - 6)
Area of parallelogram= 1/2*(sum of parallel sides) × (altitude between parallel sides)
Area of parallelogram= 1/2 × 2(x+2)× (x-6)
x^2 - 2 = x^2 - 6x + 2x-12
x^2 cancel out each other
-2 = x-12
x= 12- 2
x = 10
Hence , area of parallelogram= x^2 - = 10^2 - 4 = 96 cm^2