Question

Q.17.The length of a rectangle is 2 com more than its breadth. If the length is 3 cm more than twice its breadth, the
perimeter of the new rectangle becomes 18 cm more. Find the dimensions of the original rectangle.​

Answer 1

Answer:

let breadth-Xcm. it will 28cm

length-2x+2cm

perimeter of the rectangle-2(l+b)

28=2(2x+2+x)

28=2(2+3x)

28=4+6x

28-4=6x

24/6=x

4=×

so breadth 4cm l =2x4+2=10cm.

Step-by-step explanation:

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Answer 2

Given :-

• Length of a rectangle is 2 com more than its breadth.
• If the length is 3 cm more than twice its breadth, the
• perimeter of the new rectangle becomes 18 cm more.

Solution :-

Let Original Breadth of Rectangle is x cm.

Than, Length = (x + 2)cm.

→ Perimeter = 2(l + b) = 2 (x + x + 2) = 2(2x + 2) = (4x + 4) cm.

Now,

→ breadth = x

→ New Length = (2x +3)

→ New Perimeter = 2(2x + 3 + x) = 2(3x + 3) = (6x + 6)cm.

Given That, perimeter of the new rectangle becomes 18 cm more .

So ,

→ (6x + 6) - (4x + 4) = 18

→ 2x + 2 = 18

→ 2(x + 1) = 18

→ (x + 1) = 9

→ x = 8 cm. = Original Breadth.

And,

→ Original Length = (x + 2) = (2+8) = 10cm.

Hence, the dimensions of the original rrectangle are 8cm and 10cm.