Question

Q 17. The perimeter of the rectangle is 12 m. The length of the rectangle is
two times the breadth. Find the sides of the rectangle?​

Answer 1

Step-by-step explanation:

let the breadth be x

and length be 2x

perimeter=12 m

perimeter=2(l+b)

by putting the value of length and breadth

12=2(2x+x)

12/2=3x

6=3x

6/3=x

2=x

therefore, breadth=2 m

length=2x2=4 m

I hope this will help you

please mark me as brainlist

Answer 2

ANSWER:

• Length of rectangle = 4m
• Breadth of rectangle = 2m

GIVEN:

• Perimeter of rectangle = 12 m.
• Length of rectangle = 2(Breadth of rectangle)

TO FIND:

• Length and breadth of rectangle.

SOLUTION:

Let the breadth of rectangle be 'x'

According to Question :

Length will be '2x'

Formula:

• Perimeter of rectangle = 2(Length+ Breadth)

Putting the values in the formula:

=> 12 = 2(2x+x)

=> 12 = 2(3x)

=> 12 = 6x

=> x = 12/6

=> x = 2

Breadth of rectangle = 2 m

Length of rectangle = 2x

= 2(2)

= 4 m

NOTE:

Some important formulas:

Area of Square = (Side)²

Area of rectangle = Length*Breadth

Area of rhombus = Base*Altitude

Area of parallelogram = Base*Altitude

Area of Triangle = (Base*Altitude)/2

Perimeter of Square = 4(side)

Perimeter of rectangle = 2(length+breadth)