Math, asked by priyankajain001, 2 months ago

Q.18 "A" can complete a certain work in 18 days and 'B' can do the same wor
in 15 days."B" worked for 10 days and left the job. In how many days ca
'A' alone finish the remaining work?
1) 5 days 2) 51/2 days 3) 6 days
4) 8 days

Answers

Answered by leehun
1

Answer:

hope it's helpful to you

Step-by-step explanation:

b worked for 10 days. So, remaining 5 days work is pending. This is 5/15 = 1/3rd of work. a can finish the work in 18 days.

Answered by tennetiraj86
3

Answer:

Option 3

Step-by-step explanation:

Given:-

A" can complete a certain work in 18 days and 'B' can do the same work in 15 days."B" worked for 10 days and left the job.

To find:-

In how many days can 'A' alone finish the remaining work?

Solution:-

Given that

Number of days that A can finish the work =

18 days

A can finish the work in 1 day = 1/18 th part of the work

Number of days the B can finish the same work =

15 days

B can finish the work in 1 day = 1/15th part of the work

Number of days B worked before left = 10 days

Total working part of B = 10×(1/15)

=> 10/15

=> 2/3

So remaining work will be

part of A + Part of B = 1

Part of A = 1- Part of B

Part of A = 1-(2/3)

=> (3-2)/3

=> 1/3

Remaining work = Part of A = 1/3

Number of days that A can finish the work alone

= Total working days of A× working part of A

= 18×(1/3)

=> (18/3)

=> 6 days

Answer:-

'A' alone can finish the remaining work in 6 days

Similar questions