Question

Q. 18. A car falls off a ledge and drops to the ground in 0.5 s. Let g=10ms↑(-2)
(i) What is the speed on striking the ground?
(it) What is the average speed during the 0.5 s?
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Answer 1

Answer:

i) Vf= 5 m/s

it) V= 5/2 m/s or 2.5 m/s

Explanation:

GIVEN:

g=10 m/s²

t=0.5 s

i) Required:

Vf=?

FORMULA:

Vf=Vo+gt

In dropping bodies Vo=0, hence

SOLUTION

Vf=0+(10m/s²)(0.5s)

Vf=5m/s

it) Required:

V(ave)=?

FORMULA:

V(ave)=(Vf+Vo)/2

SOLUTION:

V(ave)=(Vf+Vo)/2

V(ave)=(5 m/s+0 m/s)/2

V(ave)=5/2 m/s or 2.5 m/s