Q.18 The angle of elevation of the top of a tower from a point in the ground, which is 10m away from
the foot of the tower, is 30°. Find the height of the tower.
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Step-by-step explanation:
Let, tower be AB
Let, point be C
Distance of point C from foot of tower = 10 m
Hence, BC = 10m
Angle of elevation = 30°
So, angle ACB = 30°
Since , tower is vertical
Angle ABC = 90°
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