Q.19) Find the sum of 15 consecutive cubes starting from 1.
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Answer:
The formula is such that 1^3+2^3+3^3+....…..……+n^3=[n(n+1)/2]^2
So here according to the question, n=15
Therefore, the sum of 15 consecutive cubes from 1 is [15×16/2]^2=14400.
Hope that helps.
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