Question

Q.19 Read the following passage and answers any four questions from 190 to 19(v),
Ravi wanted to fix the rear-view mirror of his scooter. He knows that rear-view mirror is an essential safety
device in the vehicle and allows him to see objects at the backside of his vehicle. He bought two mirrors MI
and Me, out of which Ml is curved inwards and M2 is curved outwards.
196) Based on the given situation, which mirror should Ravi need to fix as his rear-view mirror?
(a) MI (b) MBIC) Both MI and M2 (d) None of these
19(ii) If R is the radius of curvature of a spherical mirror and fis its focal length, then
(1) R=r(b)R-21(c) R-31 (d) R-1/2
19(iii) what is the formula for magnification obtained with a mirror?
Ka) Image distance
Object distance
(b) 2x Focal length
(c) Height of object
Height of image
(d) None of these
19(iv) Ravi did some preliminary experiment with mirror Mi and found that magnification of the real image of an
object placed at 10 cm in front of it is 3, at what distance is the image located?
(a) 30 cm (b) -10/3 cm (c) 10/3 cm (d) -30 cm
1904) In the magnification of a mirror has a plus sign, then the nature of imnge formed by it is:
(a) Real and inverted (b) virtual and inverted (c) virtual and erect (d) real and erect​

Answer 1

19.1)M2

19.2)R=2f

these two answers only I know any one please send rest others

Answer 2

Explanation:

1. M2

2. R=2F

3. None of these

4. 30 cm

Explanation for part 4 =

m = -3 ( because In mirror magnification is always negative )

u = -10 (given)

m = - v/u

-10 = - v/-3

-10 ×-3 = -v

-30 = v

So, distance in front of mirror is 30 cm . ☺️

HOPE ITS HELP FULL