Question

Q. 19.The controversial artificial sweetener saccharin has the molecular.
formula C3H505NSC3H505NS. What is the mass in grams of one
molecule? Atomic weights: C = 12.01, H = 1.008, 0 = 16.00, N = 14.01, S =
32.06.
O
a)5.55x10^-21
b)3.85x10^-22
c)2.24x10^-22
d)2.24x10^-21
e)Other name it​

Answer 1

Answer:

I MOLE(6*10^23) WILL WEIGH  3*12+5+80+14+32+36+5+80+32+14 =334GRAM

SO MASS OF 1 MOLECULE IS

334/6*10^23=5.55*10^-21

Explanation:

Answer 2

Answer:

5.5 × 10⁻²² g is the mass of one molecule.

Calculation:

Find the molecular mass of artificial sweetener saccharin.

$C_{3}H_{5}O_{5}NSC_{3}H_{5}O_{5}NS$

C - 6 × 12.01 = 72.06

H - 10 × 1.008 = 10.08

O - 10 × 16 = 160

N - 2 × 14.01 = 28.02

S - 2 × 32.06 = 64.12

72.06 + 10.08 + 160 + 28.02 + 64.12 = 334.28

Now find the mass of one molecule of saccharin.

334.28 g/mol = 6.02 × 10²³

$x$ g/mol = 1

$\frac{334.28}{6.02*10^{23} }$ = 5.5 × 10⁻²²g