Physics, asked by savrikhadke, 9 months ago

Q.19) Two stars emit maximum radiation at
wavelength 3600 A.U and 4800 A.U The
ratio of their temperature is
O 1:2
O 3:4
O 4:3
02:1

Answers

Answered by amoghnasa

1

Answer:

from stefans law, 3:4

Explanation:

lambda = bT

lambda1/lambda2 = 3600/4800

T1/T2= 36/48

thus, T1/T2=3/4

thus, the ratio will be, 3:4

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