Question

Q 1a for what value of Ro is the polynomial
(2x-32ks +3+ 6) олди ойлдоо олон
2​

Answer 1

Answer:

Answer:

k = 1

Step-by-step explanation:

Polynomial : 2x^4 + 3x^3 + 2kx^2+3x+62x

4

+3x

3

+2kx

2

+3x+6

Since (x+2) divides the polynomial completely

So,

\begin{gathered}p (x)=x+2\\p (x)=0\\So, x+2=0\\x=-2\end{gathered}

p(x)=x+2

p(x)=0

So,x+2=0

x=−2

We put -2 in the place of x

2x^4 + 3x^3 + 2kx^2+3x+6=02x

4

+3x

3

+2kx

2

+3x+6=0

2(-2)^4 + 3(-2)^3 + 2k(-2)^2+3(-2)+6=02(−2)

4

+3(−2)

3

+2k(−2)

2

+3(−2)+6=0

16-24+ 8k-6+6=016−24+8k−6+6=0

8k=88k=8

k = 1

Hence the value of k is 1