Question

Q.1The zeroes of x^2–2x –8 are:​

Answer 1

Answer:

4,-2 are zero this is the answer of this question

Answer 2

Answer:

Hey!! Ur answer:

${x}^{2} - 2x - 8 \\ = {x}^{2} - 4x + 2x - 8 \\ = x(x - 4) + 2(x - 4) \\ = (x + 2)(x - 4) \\ \\ zeroes \: of \:the \: polynomial \: are: \\ x = ( - 2) \: \: and \: (4)$

Step-by-step explanation:

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