Question

Q.1Write the smallest digit in the blank space of each of the following numbers so that the number formed is divisible by 9 :
(a)67_19
(b)538_8

Answer 1

Answer:

SOLUTION:

we can find the missing number by firstly finding the sum of digits of the given numbers and then subtract it from those multiple of 3, which are greater than this sum to get the smallest and greatest digits.

i) 6+7+2+4=19

multiples of 3 greater than 19 are 21,22,27,30

therefore, 21-19=2, 24-19=5, 27-19=8, 30-19=11

smallest digit=2 greatest digit=8

ii) 4+7+6+5+2=24

24 is a multiple of 3 so smallest digit is 0 greater than 24 are 27,30,33,36

27-24=3, 30-24=6, 33-24=9 36-24=12

smallest digit=0 and greatest digit=9

i hope it's clear to u...

Answer 2

A6 7419 is divisible by 9

b 538 38 is divisible by 9

Step-by-step explanation:

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