Question

Q.2)
(1
Let fand g be the function from the set of integers to itself, defined by f(x) = 2x
+ 1 and g(x) = 3x + 4. Then the composition of fand g is
marks )
Ans.
6x + 8
6x + 9
6x + 7
6x + 6​

Answer 1

$\textbf{Given:}$

$\mathsf{f(x)=2x+1}$

$\mathsf{g(x)=3x+4}$

$\textbf{To find:}$

$\textsf{Composition of f  and g}$

$\textbf{Solution:}$

$\textsf{Consider,}$

$\underline{\textsf{Composition of f and g:}}$

$\mathsf{=(f\;\circ\;g)(x)}$

$\mathsf{=f[g(x)]}$

$\mathsf{=f[3x+4]}$

$\mathsf{=2(3x+4)+1}$

$\mathsf{=6x+8+1}$

$\mathsf{=6x+9}$

$\implies\boxed{\mathsf{(f\;\circ\;g)(x)=6x+9}}$

$\textbf{Find more:}$

If f(x) = 2x² +3,g(x) = 5x - 2, then find

(a) f.g

(b) g.f

(c) f.f

(d) g.g​

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