Question

ᴘʟꜱ ɢɪᴠᴇ ᴍᴇ ᴛʜᴇ ᴀɴꜱᴡᴇʀ ᴏꜰ Q-2.

ɪʀʀᴇʟᴇᴠᴀɴᴛ ᴀɴꜱᴡᴇʀꜱ ᴡɪʟʟ ʙᴇ ʀᴇᴘᴏʀᴛᴇᴅ.
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Answer 1

Answer:

hope this answer helps you

Answer 2

$\large\bf\underbrace{\red{SOLUTION:-}}$

GIVEN :-

• The point (2k - 3 , k + 2) lie on the graph of the equation “2x + 3y + 15 = 0” .

So, Here

• x = (2k - 3)
• and y = (k + 2)

(✧) Putting the value of ‘x’ and ‘y’ in the given equation, we get the value of ‘k’ .

CALCULATION :-

$\rm{\purple{\boxed{2\:(2k\:-\:3)\:+\:3\:(k\:+\:2)\:+\:15\:=\:0\:}}}$

$\rm{\implies\:4k\:-\:6\:+\:3k\:+\:6\:+\:15\:=\:0\:}$

$\rm{\implies\:7k\:+\:15\:=\:0\:}$

$\checkmark\:\rm{\underline{\red{\boxed{\implies\:k\:=\:{\dfrac{-15}{7}}\:}}}}$