Q. 2.47. Neon gas is generally used in the sign boards If it emits strongly at 616 nm, calculate (a) the
frequency of the emission (b) distance travelled by this radiation in 30 s (e) energy of quantum
(d) number of quanta present if it produces 2J of energy.
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Explanation:
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a) The frequency of emission is
λ
c
=
616×10
−9
3.0×10
8
=4.87×10
14
.
(b) The distance travelled in 30 s is
d=t×λ×ν
=30×616×10
−9
×4.87×10
14
=9.0×10
9
m.
(c) The energy of quanta is E=hν=6.626×10
−34
×4.87×10
14
=3.227×10
−19
J.
(d) The number of quanta in 2J of energy is
3.227×10
−19
2
=6.2×10
18
photons.
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