Question

Q 2 +7x+3 solve by splitting middle term

Answer 1

Considering the equation as 2x²+7x +3 =0
2x²+7x +3 =0
⇒2x² +6x+x +3 =0
⇒2x(x+3)+1(x+3)=0
⇒(x+3)(2x+1) =0
⇒(x+3) =0 or (2x+1) =0
⇒x = -3 or -1/2

Answer 2

The correct answer is "x= -1/2" and "x= -3".

Step-by-step explanation:

$The \ given \ equatin \ is:\\2x^2+7x+3=0\\On \ factorizing \ the \ above \ equation,we \ get\\2x^2+6x+x+3=0\\2x(x+3)+1(x+3)=0\\(2x+1)(x+3)=0\\2x+1=0\\2x=-1\\x=-\frac{1}{2}\\ Or,\\x+3=0\\x=-3$

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