Question

Q.2
A die is tossed once. Find the probability of getting:
(i) a number 4 (ii) a number greater than 4 (iii) an even number (iv) a number less than 4​

Answer 1

Answer:

Total no. of outcomes=1,2,3,4,5,6

a) p(getting a number 4)=1/6

b) p(getting a number greater than 4)=2/6=1/3

c) p(getting an even number)=3/6=1/2

d) p(getting a number less than 4)=3/6=1/2

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Answer 2

Answer:

1) case 1st a number of getting 4 is one

2) case 2nd a number getting greater than 4 is 2

3) case 3rd an even number is 3

4) case 4th a number getting less than 4 is 3