Question

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(Q.2. A farmer moves along the boundary of
a square field of side 10 m in 40 s. What will be
the magnitude of displacement of the farmer at
the end of 2 minutes 20 seconds?​

Answer 1

Answer:

no. of round farmer completes in 2m 20s

= 2m 20s / 40s = 140 / 40 = 3.5 rounds

so the farmer completes 3.5 rounds

which mean displacement is the diagonal of square

so it forms a right triangle and displacement is the hypotnuese of truangle

by pythagoras theorem

h^2 = p^2 + b^2

h^2 = 10^2 + 10^2

h = (100 + 100)^1/2 = 200^1/2 = 10(2)^1/2

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Answer 2

Answer:

Farmer takes 40 s to move along the boundary. Thus, after 3.5 round farmer will at point C of the field. Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from initial position.