Question

Q.2(a) In an electric bulb 0.50 amp current is passing with the help of a generator of e.m.f source 220 Volt, find out the power of bulb.
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Answer 1

$\huge \sf {\purple{\underline {\pink {\underline { Answer᭄\ }}}}}$

Given :-

Current (I) = 0.50 ampere

Potential difference = 220 Volts

To find :-

Power = ?

Solution :-

$\begin{gathered}\dag\;{\underline{\frak{As\;we\;know\;that,}}}\end{gathered}$

$\sf{P = V \ x \ I }$

$\begin{gathered}\dag\;{\underline{\frak{Putting\:values\:in\:formula,}}}\end{gathered}$

$\sf\red{↠}$P = 220 x 0.50

$\sf\red{↠}$P = 110 Watts

${\huge{\underline{\small{\mathbb{\red{HOPE\:IT\:HELPS\:UH :)}}}}}}$