Question

Q.2. A man gives 30% of his property to his wife, 50% of the rest to his son and

divides equally rest of his property among his two daughters. If each of his

daughter receives Rs, 49000. Find his property.​

Answer 1

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Given :

Percentage Property given to his wife is 30%

Percentage Property given to his son is 50%

The remaining property shared equally between two daughters

Amount reacieved by each daughter is Rs.49,000

To Find :

The property of the Man

Solution :

% Property given to two daughters

= 100% - %Property given to wife + % Property given to son

%Property given to two daughters = 100% - (50% + 30%)

%Property given to two daughters = 100% - 80%

%Property given to two daughters = 20%

Let the property of the Man be 'a'

Then the Property given to the two daughters is 20% of a = 20a/100

We are given that Amount recieved by each daughter is Rs.49,000

Now amount recieved by the two daughters is Rs.49,000 × 2 = Rs.98,000

But We got the property given to two daughters as 20a/100

∴ The Man's Property is Rs.4,90,000