Q-2(a) n electrons, each carrying a charge -e, are flowing across a unit Cross-section of a metallic wire in unit time from east to west. write an expression for electric current and also give its direction of flow. give reason for your answer.
(b) The charge possessed by an electrons is 1.6×10^-19 coulomb. find the number of electrons that will flow per second to constitute a current of 1 ampereampere
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( a ) I=Q/T
Electric current will flow feom west to east because the conventional flow of current will be always in the direction opposite to the direction of flow of electrons.
( b ) The current is defined as rate of flow of charged particle.i.e.
i = Q / t
Hence the charge flown is,
Q =i t
Hence Q =1.0×1=1C
The charge Q is due to electrons, therefore,
Q =N×e
Here Q =1C
If N is number of electrons passing and e is the electronic charge of value 1.6×10−¹⁹
Then,
N = Q/ e
= 1/ 1.6×10-¹⁹
=0.625×10¹⁹ electrons
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