Q.2
A particle of mass 20 g is released with an initial velocity 5 m/s along the curve from the point A, as shown
in the figure. The point A is at height h from point B. The particle slides along the frictionless surface, when
the particle reaches point b, its angular momentum about O will be:
(Take g= 10 m/s)
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A particle of mass 20g is released with an initial velocity 5m/s along the curve from the point A, as shown in the figure. The point A is at ...
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Work - Energy Theorem from A to B mgh = 1g mv^2B - 1g mv^2A 2gh = v^2B - v^2A 2 × 10 × 10 = v^2B - 5^2 vB = 15 m/s Angular momentum about 0 L0 =
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