Math, asked by smithjaden, 4 months ago

Q.2)
(a) The nth term of a sequence is 60-8n.
Find the largest number in this sequence.

Answers

Answered by sumanthbhat99
26

Answer:

52

Step-by-step explanation:

1st term is =60-8=52

a2=60-16=44

a3=60-24=36

a4=60-32=28

a5=60-40=20

a6=60-48=12

....

sI the terms are 52,44,36,28, 20,12,4,-4,-12....

so the largest term is 52

Answered by pulakmath007
1

SOLUTION

GIVEN

The nth term of a sequence is 60 - 8n

TO DETERMINE

The largest number in this sequence

EVALUATION

Here it is given that the nth term of a sequence is 60 - 8n

 \sf{Let \:  a_n \:  \:  be \:  the \:  nth \:  term \:  of  \: the  \: sequence }

 \sf \: Then  \:  \:  \: a_n = 60 - 8n

 \sf \therefore  \:  \:  \: a_{n  + 1}= 60 - 8(n + 1)

 \sf \implies  \:  \:  \: a_{n  + 1}= 60 - 8n  - 8

 \sf \implies  \:  \:  \: a_{n  + 1}= 52 - 8n

Now have

 \sf  \:  60 > 52\:

 \sf \implies  \:  60 - 8n > 52 - 8n\:

 \sf \implies  \:  \:  a_{n } > \: a_{n  + 1}

So the given sequence is decreasing

Hence the largest term of the sequence

= First term of the sequence

 \sf = a_{1}

 \sf = 60 - (8 \times 1)

 \sf = 60 - 8

 \sf = 52

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