Question

Q-2 A train starting from rest attains a velocity of 30m/s in 300 seconds. Find the acceleration.​

Answer 1

Explanation:

a=v-u/t

a = 30-0/300

a= 0.1 m/s2

Answer 2

${\huge{\sf{\underline{\red{Given :}}}}}$

A train starting from rest attains a velocity of 30m/s in 300 seconds.

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${\huge{\sf{\underline{\blue{To Find:}}}}}$

Find the acceleration of the train.

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${\huge{\sf{\underline{\green{ Formula Used:}}}}}</p><p>$

${\sf{\red{Acceleration = \frac{v - u}{t} }}}$

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${\huge{\sf{\underline{\orange{ Solution :}}}}}$

$u = 0m \: {s}^{ - 1}$

$v = 30m \: {s}^{ - 1}$

$t = 300s$

$a = \frac{v - u}{t}$

$a = \frac{30 - 0}{300}$

$a = 0.1m \: {s}^{ - 1}$

Hence,

${\sf{\boxed{\red{a = 0.1m \: {s}^{ - 1} }}}}$

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