Question

Q.2 An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and nature of the image formed.

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Answer 1

Answer:

1/f = 1/v €“ 1/u

1/v = 1/10 -1/15

1/v = 3/50

V = 50/3 cm.

The image is real and inverted at a distance of 16.7 cm from the lens on opposite side. Magnification (m) = hi/h0= v/u

hi /5 =16.7/-25

hi = -10/3 cm.

Image is inverted and diminished.

Answer 2

Answer :

$\bf{\red{\underline{\bf {Given:-}}}}$

$\bf{\blue {\underline{\bf {Mirror \: formula :-}}}}$ 1/f = 1/v-1/u

1/v = 1/10-1/25

1/v = 3/50

v = 50/3

v = 16.7 cm

The image is real and inverted at a distance of 16.7cm from the lens opposite side magnification (m)=hi/ho=-v/u

$= \frac{hi}{5} = \frac{16.7}{25} \\ = hi = \frac{16.7 \times 5}{25 } \\ hi = \frac{16.7}{5} \\ hi = 3.34cm$

Image is inverted and diminished..

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