Question

Q.2 Fill in the blanks
(1) if radius and height of cone is 1,2 then volume of cone​

Answer 1

Answer :-

• The Volume of cone is 2.095 cubic units.

Step-by-step explanation :

To Find :-

• The volume of cone

Solution :-

Given that,

• Radius of cone = 1 units
• Height of cone = 2 units

Therefore,

As we know that,

$\underline{ \boxed{\bf{Volume \: of \: cone = \dfrac{1}{3} \: \pi \: {r}^{2}h}}}$

According the question,

$\sf{ \longmapsto \: \dfrac{1}{3} \: \pi \: {r}^{2}h} \\ \\ \\ \sf{ \longmapsto \: \dfrac{1}{3} \times \pi \times {r}^{2} \times h} \\ \\ \\ \sf{ \longmapsto \: \dfrac{1}{3} \times \dfrac{22}{7} \times {(1)}^{2} \times 2} \\ \\ \\ \sf{ \longmapsto \: \dfrac{1}{3} \times \dfrac{22}{7} \times 1 \times 1 \times 2} \\ \\ \\ \sf{ \longmapsto \: \dfrac{1}{3} \times \dfrac{22 \times 1 \times 1 \times 2}{7}} \\ \\ \\ \sf{ \longmapsto \: \dfrac{1}{3} \times \dfrac{22 \times 2}{7}} \\ \\ \\ \sf{ \longmapsto \: \dfrac{1}{3} \times \dfrac{44}{7}} \\ \\ \\ \sf{ \longmapsto \: \dfrac{44}{7 \times 3}} \\ \\ \\ \sf{ \longmapsto \: \dfrac{44}{21}} \\ \\ \\ \sf{ \longmapsto \: \cancel{\dfrac{44}{21}}} \\ \\ \\ \bf{ \longmapsto \: 2.095 \approx}$

• The Volume of cone is 2.095 cubic units.