Question

Q-2 Find a quadratic polynomial each with the given numbers 4 and 1 as the sum

and product of zeroes respectively​

Answer 1

Answer:

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Step-by-step explanation:

1) 1/4 , -1

Given

Alpha + beta =1/4

Alpha ×beta =1

x^2 -(aplha +beta)x + aplha×beta

Putting constant term as K

K(x^2 -(aplha +beta)x + aplha×beta)

Now putting the values

K( x^2-1/4x + (-1)=0

So we get ,

K ( x^2-1/4x -1)=0

Or

By dividing 4 we get

K (4x^2-x-4)=0

Answer 2

Answer:

$\underline{ k(x^2-4x+1)}$

Step-by-step explanation:

$\text{sum of zeroes = 4} \\ \text{product of roots = 1} \\\\ \text{then the quadratic polynomial will be in the form of } \\ => \bf{k(x^2 - (sum \ of \ roots)x + (product \ of \ roots))} \ \ \ \ [k \ is \ any \ constant] \\ \\ =>k(x^2-4x+1) \\\\ {\textit{the required polynomial is}} \ \ \underline{ k(x^2-4x+1)}$