Question

Q.2 Find Molality. 1) 15g urea dissolved in 400g of water.​

Answer 1

Explanation:

$molar \: mass \: of \: urea(NH_2CONH_2) \\ = 2 \times 14 + 1 \times 4 + 12 + 16 \\ = 60 \: g {mol}^{ - 1} \\ mass \: of \: urea = 15 \: g \\ mass \: of \: water = 400 \: g = 0.4 \: kg \\ n_{urea} = \frac{given \: mass}{molar \: mass} \\ = \frac{15}{60} =0.25 \: mol \\ molality(m) = \frac{moles \: of \: solute}{mass \: of \: solvent \: (kg)} \\ = \frac{0.25}{0.4} \\ = 0.625 \: mol {kg}^{ - 1} or \: m \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$