Q. 2. Find the area of a quadrilateral ABCD, the co-
ordinates of whose vertices are A(-3, 2), B(5, 4),
C(7,-6) and D(-5,-4).
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Answer: Area of quadrilateral = 80 sq. units
Step-by-step explanation:
Area of the quadrilateral = 1/2 {(x1 * y2 + x2 * y3 + x3 * y4 + x4 * y1) - (y1 * x2 + y2 * x3 + y3 * x4 + y4 * x1)}
= 1/2 {(-12-30-28-10) - (10+28+30+12)}
= 1/2 {(-80-80)}
= 1/2 (-160)
= -80
Therefore, Area of quadrilateral = 80 sq. units
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