Q:2 find the area of a rhombus if each of its sides measure 41 cm and one of the diagonal is 80 cm answer
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Let d1 ,d2 are the diagonals and length of the side is x of a rhombus , then
(d1/2)^2+(d2/2)^2=(x)^2. , putting x=41 cm and d1= 80 cm.
(80/2)^2+(d2/2)^2= (41)^2
or. (d2/2)^2=1681–1600=81
or. d2/2=9 => d2= 18 cm.
Area of the rhombus = 1/2.d1×d2. = 1/2.×80×18 = 720 cm^2
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