Q.2) Find the value of x ifx2 - x +1 x +1x+1 x+1)= 0
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= x² - x + 1x +1x +1x +1=0
=x²+2x+1 =0
=x²+(1+1)x +1 = 0
=x²+x + x + 1= 0=
=x(x+1)+1(x+1)=0
=(x+1) (x+1)=0
i.e., x+1= 0 or x+1= 0
x=-1 or x=-1
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