Q.2: Find the value of x in the given fig.
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Answer:
Refer to the attachment...
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Hope it helps...
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Answer:
In the given figure:-
Angle DFB+Angle CFB=180° (angles in a straight line)
95°+Angle CFB=180°
Angle CFB=180°-95°
=85°
Now,
angle ABC+angle CBF=180° (angles in a straight line)
120°+angle CBF=180°
angle CBF=180°-120°
=60°
Now,
In triangle BCF
angle B+angle C+angle F=180°(Sum of angles of a triangle =180°)
60°+x+85°=180°
145°+x=180°
x=180°-145°
=35°
x=35°
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