Question

Q. 2. (i) Which term of series
64 + 32 + 16 + 8 + ... is 1/64 ?

Answer 1

Step-by-step explanation:

first term(a)=64

difference(d)=32-64=-32

an=1/64

an=a+(n-1)d

1/64 =64+(n-1)(-32)

-3305 = (n-1)

64×(-32)

3305 = (n-1)

2048

5353 =n

2048

n is in fraction so 1/64 is not the part of A.P

HOPE IT HELPS YOU.....

MARK IT AS BRAINLIEST ANSWER