Question

Q.2 If a and b are zeroes of the polynomial x² – p(x + 1) + c such that

(a+1)(b+1) = 0, then find the value of c.​

Answer 1

Answer:

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Step-by-step explanation:

have,

f(x)=x² −p(x+1)−c=0

f(x)=x²−px−(p+c)=0 .............(1)

Since,

α,β are the zeroes of the above polynomial.

So,

α+β=p

αβ=−(p+c)

Since,

(α+1)(β+1)=0

αβ+α+β+1=0

−p−c+p+1=0

−c+1=0

c=1