Question

Q.2 If a and b are zeros of p(x) =x^2+x-1 then find 1/a+1/b.​

Answer 1

Given:

• a and b are the zeroes of p(x)= x²+x-1 .

To find :

• 1/a + 1/b

Solution:

P(x) = x²+x-1

Here,

• a= 1

• b = 1

• c = -1

As we know that,

• Sum of zeroes (a+b) = -b/a = -1/1=-1

• product of zeroes (ab) =c/a= -1/1=-1

$\implies \: \frac{1}{a} + \frac{1}{b} \\ \\ \implies \: \frac{b + a}{ab} \\ \\ \implies \: \cancel{\frac{ - 1}{ - 1} } \\ \\ \implies \: 1$

Hence , tha value is 1 .

Answer 2

Step-by-step explanation:

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