Q.2 If the HCF (1152, 1664) = 128, then LCM (1152, 1664) is equal to Choose one: 1916928 7488 4992 14976
Answers
Answered by
64
Hi ,
***************************
If a , b are two positive Integers and their
HCF = H , and LCM = L then
a × b = H × L
************************************"**
Now ,
a = 1152 ,
b = 1664 ,
H = 128 ,
L = ?
L × H = a × b
L = ( a × b )/H
L = ( 1152 × 1664 )/128
L = 14976
Therefore ,
Required LCM = 14976
I hope this helps you.
: )
***************************
If a , b are two positive Integers and their
HCF = H , and LCM = L then
a × b = H × L
************************************"**
Now ,
a = 1152 ,
b = 1664 ,
H = 128 ,
L = ?
L × H = a × b
L = ( a × b )/H
L = ( 1152 × 1664 )/128
L = 14976
Therefore ,
Required LCM = 14976
I hope this helps you.
: )
Answered by
28
Hiii friend,
One Number = 1152
other number = 1664
HCF of two numbers = 128
LCM of two numbers = ?
we know that,
One Number × Other Number = HCF × LCM
1152 × 1664 = 128 × LCM
LCM = 1152×1664/128
LCM = 14976
Hence,
option (D) is the right answer..
HOPE IT WILL HELP YOU..... :-)
One Number = 1152
other number = 1664
HCF of two numbers = 128
LCM of two numbers = ?
we know that,
One Number × Other Number = HCF × LCM
1152 × 1664 = 128 × LCM
LCM = 1152×1664/128
LCM = 14976
Hence,
option (D) is the right answer..
HOPE IT WILL HELP YOU..... :-)
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