Math, asked by Nathiya7308, 1 year ago

Q.2 If the HCF (1152, 1664) = 128, then LCM (1152, 1664) is equal to Choose one: 1916928 7488 4992 14976

Answers

Answered by mysticd
64
Hi ,

***************************

If a , b are two positive Integers and their

HCF = H , and LCM = L then

a × b = H × L

************************************"**

Now ,

a = 1152 ,

b = 1664 ,

H = 128 ,

L = ?


L × H = a × b

L = ( a × b )/H

L = ( 1152 × 1664 )/128

L = 14976

Therefore ,

Required LCM = 14976

I hope this helps you.

: )
Answered by Panzer786
28
Hiii friend,

One Number = 1152

other number = 1664

HCF of two numbers = 128

LCM of two numbers = ?

we know that,

One Number × Other Number = HCF × LCM

1152 × 1664 = 128 × LCM

LCM = 1152×1664/128

LCM = 14976

Hence,

option (D) is the right answer..


HOPE IT WILL HELP YOU..... :-)
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