Question

Q.2 If the product of zeroes of the polynomial ax? – 6x – 6 is 4, find the
value of a. Find the sum of the zeroes of the polynomial.​

Answer 1

Answer:

here,

ax²-6x-6=0

a=a,b=-6,c=-6

product of zeros=4

c/a=4

-6/a=4

a=-6/4

a=-3/2

sum of zeros=-b/a

=-(-6)/-3/2

=6×2/-3

=-2×2

=-4

Answer 2

SOLUTION:-

Given:

If the product of zeroes of the polynomial ax² -6x -6 is 4.

To find:

The value of a & the sum of zeroes of polynomial.

Explanation:

We have,

The polynomial ax² -6x -6 is a quadratic equation.

Ax² + Bx +C compare with the given polynomial.

• A=a
• B= -6
• C= -6

We know that, product of the zeroes:

$\alpha \beta = \frac{c}{a}$

Therefore,

$4 = \frac{ - 6}{a} \\ \\ 4a = - 6 \\ \\ a = \frac{ - 6}{4} \\ \\ a = - \frac{3}{2}$

Thus,

The value of a= -3/2.

&

Sum of the zeroes of the polynomial:

$\alpha + \beta = \frac{ - b}{a}$

Therefore,

$\alpha + \beta = - \frac{ ( - 6)}{ \frac{ - 3}{2} } \\ \\ \alpha + \beta = 6 \times - \frac{2}{3} \\ \\ \alpha + \beta = - \frac{12}{3} \\ \\ \alpha + \beta = - 4$

Sum of the zeros is -4.