Question

Q.2. If the zeroes of x2 – px + 6 are in the ratio 2:3 find p
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Answer 1

p(x) = x² - px + 6

Given, zeroes = 2x : 3x

Product of zeroes = (constant term) / (coefficient of x² )

==> 2x × 3x = 6

==> 6x² = 6

==> x² = 1

==> x = 1 , -1

x = 1

Zeroes are = 2x , 3x ==> 2, 3

==> sum of zeroes = - (coefficient of x) / (coefficient of x² )

==> 2 + 3 = -(-p)/1

==> p = 5

When, x = 1, we get p = 5

x = -1

Zeroes are = 2x , 3x ==> -2, -3

==> sum of zeroes = -(coefficient of x) / (coefficient of x²)

==> -2 - 3 = -(-p)/1

==> p = -5

When, x = 1, we get p = -5

Answer 2

Answer:

k = 5 and -5.

Step-by-step explanation:

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